Which carbohydrate provides energy for cows but only dietary fiber for humans? A-cellulose B-starch C-glycogen D-sucrose
Solution 1
A - Cellulose
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Solution 2
📚 Related Questions
I just took the test and got it right!
Answer : The correct answer for mole ratio of H₂O : H₃PO₄ = 6: 4 .
Mole ratio :
It is defined as mole of one substance to another substance in a balanced reaction . In the balanced reaction , the coefficient written before the substances are taken as moles of that substance.
The given balanced reaction between P₄H₁₀ and H₂O is :
P₄O₁₀ + 6 H₂O → 4 H₃PO₄
Mole of H₂O = 6
Mole of H₃PO₄ = 4
Hence mole ratio of Water : H₃PO₄ = 6 : 4
Assuming there was no heat leaked from the system, the heat q lost by cadmium would be equal to the heat gained by the water:
heat lost by cadmium = heat gained by the water
-qcadmium = qwater
Since q is equal to mcΔT, we can now calculate for the mass m of the cadmium sample:
-qcadmium = qwater
-(mcadmium)(0.850J/g°C)(38.6°C-98.0°C)) = 150.0g(4.18J/g°C)(38.6°C-37.0°C)
mcadmium = 19.9 grams
Reduction hald reaction: 2H⁺ + 2e⁻→ H₂.
Oxidation half reaction: Mg⁰ → Mg²⁺ + 2e⁻.
In this chemical reaction, magnesium lost two electrons (oxidation, change oxidation number from 0 to +2) and hydrogen gain that two electrons (reduction, change oxidation number from +1 to 0).
ΔT = - i m Kf
when m is the molality of a solution
i = 2
and ΔT is the change in melting point = T2- 0 °C
and Kf is cryoscopic constant = 1.86C/m
now we need to calculate the molality so we have to get the moles of NaCl first:
moles of NaCl = mass / molar mass
= 3.5 g / 58.44
= 0.0599 moles
when the density of water = 1 g / mL and the volume =230 L
∴ the mass of water = 1 g * 230 mL = 230 g = 0.23Kg
now we can get the molality = moles NaCl / Kg water
=0.0599moles/0.23Kg
= 0.26 m
∴T2-0 = - 2 * 0.26 *1.86
∴T2 = -0.967 °C
Answer:
0.952 °C
Explanation:
The change in melting point is computed as:
ΔT = k*m*i
where ΔT is the difference between the melting point of water and of solution, k is a constant (1.86 °C*kg/mol for water), i is the van't Hoff factor (equal to 2 for sodium chloride because 2 ions are obtained after its dissolution), and m is the molality of the solution.
Molar mass of sodium chloride: 58.44 g/mol
Moles of of sodium chloride: mass / molar mass 3.5/58.44 = 0.059 mol
Density of water 1 kg/L
230 mL of water are equivalent to 0.23 L
mass of water: density * volume = 1*0.23 = 0.23 kg
Molality of the solution: m = moles of solute/ kg of solvent = 0.059/0.23 = 0.256
Finally:
ΔT = 1.86*0.256*2 = 0.952 °C
Water melting point: 0 °C
So, the solution melting point is: 0 - 0.952 = 0.952 °C
The shuttle can carry a maximum of 4 astronauts for one mission.
2 LiOH + CO2 -----> Li2CO3 + H2O
(3.50 × 10^4 g LiOH) (1 mol LiOH/ 24 g LiOH) ( 1 mol CO2 / 2 mol LiOH) ( 44 g CO2 /1 mol CO2) = 32, 083.33 g CO2
32, 083.33 g / 9 (8.8 × 10^2) = 4
Types of Bonds can be predicted by calculating the difference in electronegativity.
If, Electronegativity difference is,
Less than 0.4 then it is Non Polar Covalent
Between 0.4 and 1.7 then it is Polar Covalent
Greater than 1.7 then it is Ionic
For Be and F,
E.N of Fluorine = 3.98
E.N of Beryllium = 1.57
________
E.N Difference 2.41 (Ionic Bond)
For H and Cl,
E.N of Chorine = 3.16
E.N of Hydrogen = 2.20
________
E.N Difference 0.96 (Polar Covalent Bond)
For Na and O,
E.N of Oxygen = 3.44
E.N of Sodium = 0.93
________
E.N Difference 2.51 (Ionic Bond)
For F and F,
E.N of Fluorine = 3.98
E.N of Fluorine = 3.98
________
E.N Difference 0.00 (Non-Polar Covalent Bond)
Result:
A polar covalent bond is formed between Hydrogen and Chlorine atoms.
Answer:
false
Explanation: