When fracking liquid waste is left in pools on the surface, _ can evaporate into the air and contribute to pollution
Solution 1
Answer:
The answer is "toxic chemicals".
Explanation:
Hydraulic fracture uses compounds such as sand to prevent fractures from closing, chemical additives, and several hundred chemical products, some very toxic and carcinogenic, that perform the function of preventing gas and oil from becoming contaminated. They are also used to prevent corrosion. By depositing fracking liquid waste in the pools, the most volatile products tend to evaporate contributing to air pollution. Some of the elements contained in this wastewater are selenium, radio, and lead.
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Solution 2
📚 Related Questions
The character of acidic, basic and neutral is defined by the concentration of hydrogen ions [H+](mol/L). A solution with a concentration of hydrogen ions higher than 10-7mol/L is acidic, and a solution with a lower concentration is alkaline (another way to say basic). Using the formula, pH=-log[H+], a pH of 7 is neutral, a pH less than 7 is acidic, and a pH greater than 7 is basic. As one can see from this formula, ten times a given concentration of hydrogen ions means one unit lower in terms of pH value (higher acidity), and vice versa.
The formula for ph is given by:pH=−log10[H+]
What is the concentration of H+ ions at a pH = 8?
In calculating for the concentration of hydrogen ion, the formula is given by:[H+]=(10)^(-pH)
Solution:
[H+]=(10)^(-8)[H+]=0.00000001 mol/L
What is the concentration of OH– ions at a pH = 8?pH+pOH=148+pOH=14pOH=6
[OH-]=(10)^(-pOH)[OH-]=(10)^(-6)[OH-]=0.000001
What is the ratio of H+ ions to OH– ions at a pH = 2?The ratio is 0.00000001:0.000001 which is equal to 0.01
Answer:
0.00000001
0.000001
0.000001 : 1 or 1 : 100
Explanation:
answer on e2020
Pb(NO₃)₂ + 2 HCl → PbCl₂ + 2 HNO₃
According to equation,
1 mole of PbCl₂ is formed by = 1 mole of Pb(NO₃)₂
So,
8 moles of PbCl₂ will be produced by = X moles of Pb(NO₃)₂
Solving for X,
X = (8 mol × 1 mol) ÷ 1 mol
X = 8 mol of Pb(NO₃)₂
Result:
8 mol of Pb(NO₃)₂ are required to produce 8 moles of PbCl₂.
Answer:
Heat is transferred through contact between molecules.
Explanation:
a-p-e-x
A - Cellulose
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I just took the test and got it right!
Answer : The correct answer for mole ratio of H₂O : H₃PO₄ = 6: 4 .
Mole ratio :
It is defined as mole of one substance to another substance in a balanced reaction . In the balanced reaction , the coefficient written before the substances are taken as moles of that substance.
The given balanced reaction between P₄H₁₀ and H₂O is :
P₄O₁₀ + 6 H₂O → 4 H₃PO₄
Mole of H₂O = 6
Mole of H₃PO₄ = 4
Hence mole ratio of Water : H₃PO₄ = 6 : 4
Assuming there was no heat leaked from the system, the heat q lost by cadmium would be equal to the heat gained by the water:
heat lost by cadmium = heat gained by the water
-qcadmium = qwater
Since q is equal to mcΔT, we can now calculate for the mass m of the cadmium sample:
-qcadmium = qwater
-(mcadmium)(0.850J/g°C)(38.6°C-98.0°C)) = 150.0g(4.18J/g°C)(38.6°C-37.0°C)
mcadmium = 19.9 grams
Reduction hald reaction: 2H⁺ + 2e⁻→ H₂.
Oxidation half reaction: Mg⁰ → Mg²⁺ + 2e⁻.
In this chemical reaction, magnesium lost two electrons (oxidation, change oxidation number from 0 to +2) and hydrogen gain that two electrons (reduction, change oxidation number from +1 to 0).
ΔT = - i m Kf
when m is the molality of a solution
i = 2
and ΔT is the change in melting point = T2- 0 °C
and Kf is cryoscopic constant = 1.86C/m
now we need to calculate the molality so we have to get the moles of NaCl first:
moles of NaCl = mass / molar mass
= 3.5 g / 58.44
= 0.0599 moles
when the density of water = 1 g / mL and the volume =230 L
∴ the mass of water = 1 g * 230 mL = 230 g = 0.23Kg
now we can get the molality = moles NaCl / Kg water
=0.0599moles/0.23Kg
= 0.26 m
∴T2-0 = - 2 * 0.26 *1.86
∴T2 = -0.967 °C
Answer:
0.952 °C
Explanation:
The change in melting point is computed as:
ΔT = k*m*i
where ΔT is the difference between the melting point of water and of solution, k is a constant (1.86 °C*kg/mol for water), i is the van't Hoff factor (equal to 2 for sodium chloride because 2 ions are obtained after its dissolution), and m is the molality of the solution.
Molar mass of sodium chloride: 58.44 g/mol
Moles of of sodium chloride: mass / molar mass 3.5/58.44 = 0.059 mol
Density of water 1 kg/L
230 mL of water are equivalent to 0.23 L
mass of water: density * volume = 1*0.23 = 0.23 kg
Molality of the solution: m = moles of solute/ kg of solvent = 0.059/0.23 = 0.256
Finally:
ΔT = 1.86*0.256*2 = 0.952 °C
Water melting point: 0 °C
So, the solution melting point is: 0 - 0.952 = 0.952 °C