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The current size of an image on Samuel's computer is shown below: A rectangle

The current size of an image on Samuel's computer is shown below: A rectangle is shown. The length of the rectangle is labeled as length equal to 8 inches and the width is labeled as width equal to 10 inches. What are the dimensions of the image at fraction 1 over 2 times its current size

2 months ago

Solution 1

Guest Guest #1492
2 months ago

Answer:

The length and the width of image is  4 inches and 5 inches respectively

Step-by-step explanation:

Given : Length of rectangle is 8 inches

          Width of rectangle is 10 inches

To Find: What are the dimensions of the image at fraction \frac{1}{2} times its current size

Solution:

Length of rectangle is 8 inches

Since we are given that the dimensions of the image at fraction \frac{1}{2} times its current size

So, Length of image = \frac{1}{2} \times 8 = 4

Thus the length of image is 4 inches.

Width of rectangle is 10 inches

Since we are given that the dimensions of the image at fraction \frac{1}{2} times its current size

So, width of image = \frac{1}{2} \times 10 = 5

Thus the width of image is 5 inches.

Hence the length and the width of image is  4 inches and 5 inches respectively.

Solution 2

Guest Guest #1493
2 months ago
Length is equal to 4 and width is equal to 5. 

You can just divide each by 2. 

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