Solution 1
Following are the investigative question that you can answer by doing this experiment.
1) What information can be obtained from the colour of flame?
2) State the relationship between wavelength, frequency, and energy?
3) Can you identify the metal present in unknown sample provided?
4) How will you identify amount of metal present in sample solution?
5) Why do different chemicals emit light of different colour?
Solution 2
The first one is chlorine ion, the second one is metal ion.
📚 Related Questions
36.0 g of glucose divided by 180 g/mol = 0.200 moles of glucose
find molarity:
0.200 moles of glucose / 2 litres = 0.100 Molar solution
that is P1/T1 = P2/V2
P1 = 100 torr
T1 = 27+273 = 300 k
T2 =127 +273 =400 k
P2=?
by making P2 the subject of the formula
P2=T2P1/T1
=100 x 400/300 = 133.3 torr
Nuclear reaction: ¹⁰⁶Ru → ¹⁰⁶Rh + e⁻(electron) + ve(electron antineutrino).
Beta decay is radioactive decay in which a beta ray and a neutrino are emitted from an atomic nucleus.There are two types of beta decay: beta minus and beta plus.
In beta minus decay, neutron is converted to a proton and an electron and an electron antineutrino.In beta plus decay, a proton is converted to a neutron and positron and an electron neutrino, so mass number does not change.
Answer : The correct answer is oxidation number of Zn changes from 0 to +2.
Oxidation number :
It is number given to an element when it undergoes oxidation by loosing electrons . Oxidation number is equal to number of electrons donated . It is generally represented as charge .
Oxidation number of any element in a compound can be calculated as :
(Total number of positive charge) + (total number of negative charge) = total charge on compound
Where : Total positive charge = No. of atom or polyatomic molecule * positive charge on it
Total negative charge = No. of atom or polyatomic molecule * negative charge on it
Total charge on compound = Charge lying on top of compound .
Following steps can be used to find change in oxidation number of Zn :
Step 1 ) : To find oxidation number of Zn ( reactant side ) :
On reactant side Zn is present in solid state or its elemental state . It is not attached to any other atom , hence it is neutral and isolated atom. So oxidation number on Zn(s) is 0 .
Step 2: To find oxidation number of Zn in ZnSO₄ (aq)
ZnSO₄(aq) is ionic compound compound . It has two ions in it, Zn and SO₄ . Also it is a neutral compound means it has zero charge on it .
SO₄ is sulfate which has -2 charge or oxidation number on it (image attached )and there is one molecule of SO₄ ion . There is one atom of Zn which has unknown charge or oxidation number (x) .
To calculate oxidation number on Zn ion , plug values in above formula :
(No of Zn atom * charge on it ) + (No of SO₄ molecule * charge on it ) = Total charge on ZnSO₄
( 1* charge on Zn ) + ( 1* -2 ) = 0
Charge on Zn + (-2) = 0
Charge on Zn = +2
On reactant side Zn(s) has Zero charge and on product side Zn in ZnSO₄(aq) has +2 charge .
Hence the charge in oxidation number of Zn is from 0 to +2 .
Gibbs free energy (G) determines if reaction will proceed spontaneously, if ΔG is negative, reaction is spontaneous.
ΔG = ΔH - T·ΔS.
ΔG - changes in Gibbs free energy.
ΔH - changes in enthalpy.
ΔS - changes in entropy.
T is temperature in Kelvins.
explanation :
pH values of all :
battery acid pH = 1.0
vomit pH = 2.0
soda pop pH = 2.5
orange juice pH = 3.5
coffee pH = 5.0
milik pH = 6.5
pH value is lesser acidity is more . high pH indicate lesser acidic nature