Factor completely 2x^3+6x^2+2x+6

Factor completely 2x^3+6x^2+2x+6

2 months ago

Solution 1

Guest Guest #2442
2 months ago
2x^3+6x^2+2x+6
= 2(
x^3 + 3x^2 + x +  3)
= 2[x^2 (x + 3) + (x + 3)]
= 2(x^2 + 1)(x + 3)

hope it helps

Solution 2

Guest Guest #2443
2 months ago
F(-3) = 2*-27 + 6*9 + 2*-3 + 6 =  0

so x + 3 is a factor

dividing the function by x + 3  gives the quotient 

2x^2 + 2   = 2 (x^2 + 1)

So the factors are 2(x^2 + 1)(x + 3)  Answer

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