admin admin
Brett mare a scale drawing of a rectangular room in his house.The actual

Brett mare a scale drawing of a rectangular room in his house.The actual room is 12 4/5 ft.The scale used to make the drawing was 1/4 in=1ft. What is the length in inches of the room on the drawing?

2 months ago

Solution 1

Guest Guest #161
2 months ago
1/4 in : 1 ft

1 ft  ⇒ 1/4 in

12 4/5 ft ⇒ 1/4 x 12 4/5 =  1/4 x 64/5 = 3 1/5 in

Answer: 3 1/5 in

📚 Related Questions

Question
£600 is put in a bank. after a year the money has increased by 8% how much is now in the bank
Solution 1
Increased = 8% x £600 = 0.08 x 600 = £48

Money in the bank now = £600 + £48 = £648


Answer: £648
Question
For a certain manufacturer, only ⅘ of the items produced are not defective.If 2,000 items are manufactured in a month, how many are not defective?
Solution 1
To find the number of non-defective chips, we simply use this equation:
2,000 * 4/5
8000/5
Now you simply divide:
1600
1600 chips aren't defective
Question
An experienced roofer can work twice as fast as her helper. working together, they can shingle a new section of roof in 4 hours. how long would it take the experienced roofer, working alone, to complete the same job?
Solution 1
For this case, the first thing we must do is define variables.
 We have then:
 x: amount of time the assistant works
 Y: amount of time the experienced person works
 We then have the following system of equations:
 x + y = 4
 y = (1/2) x
 Solving the system we have:
 x = 8/3
 y = 4/3
 Answer:
 It would take the roofer, working alone, to complete the same job about:
 y = 4/3 hours
Question
A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the population standard deviation is
Solution 1
The 100(1-\alpha)\% confidence interval of a standard deviation is given by:

\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval, 

\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493

Therefore, the 90% confidence interval for the standard deviation is given by

\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7
Question
A map has the scale 2 centimeters = 1 kilometer. on a map, the area of a forest preserve is 3.8 square centimeters. what is the area of the actual forest preserve
Solution 1
We know that
the scale is 2 cm/1 km
on a map, the area of a forest preserve is 3.8 cm²
assuming it has a square shape
the length side of the square is √3.8 cm
so
if 2 cm on a map-----------------> is a 1 km in the actual
 √3.8 cm------------------------> x
x=√3.8/2 km

the area of the actual forest preserve is
(√3.8/2)*(√3.8/2)----> 3.8/4---> 0.95 km²

the answer is
0.95 km²
Question
(a) [5 points] using only the definition, find the laplace transform y (s) of y(t) = e a t where a is a constant. for what values of s does the laplace transform y (s) exist? (b) [10 points] solve, using laplace transforms, the initial value problem: y 00 − 4y 0 + 4y = 3, y(0) = 0, y0 (0) = 1.
Solution 1
Find the Laplace transform y (s) of y (t) = e a t. Here, a is a constant. Which value of s exists for the Laplace transform y (s)? (0) = 0, y 0 (0) = 0, y (0) = 0,

📂 Subjects

Mathematics 2647929
History 842281
English 748681
Biology 586256
Social Studies 406852
Chemistry 368373
Business 348603
Physics 324927
Health 199835
Spanish 130075
Geography 112100
Computers and Technology 106146
Arts 77164
Advanced Placement (AP) 23675
World Languages 23213
French 22589
Engineering 19607
Law 17108
Medicine 13966
SAT 10987
German 3389

🔢 Grades

High School 3423409
Middle School 2092250
College 1518097