A sample of gas occupies 10.0 l at 100.0 torr and 27.0 c. calculate the

A sample of gas occupies 10.0 l at 100.0 torr and 27.0 c. calculate the pressure if the temperature is changed to 127c while the volume remains constant. (133 torr)

2 months ago

Solution 1

Guest Guest #427
2 months ago
The pressure  of a sample  of a gas if the temperature  is changed  to 127  c  while  the volume  remains  constant   is calculated  using gay lussac law formula

that is P1/T1 = P2/V2
P1 = 100 torr
T1 = 27+273 = 300 k
T2 =127 +273 =400 k

by  making P2 the subject of the formula

=100  x 400/300 = 133.3 torr

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Identify the missing daughter nucleus in the β– emission decay of 106ru below.
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Answer is: the missing daughter nucleus is rhodium (Rh).

Nuclear reaction: ¹⁰⁶Ru → ¹⁰⁶Rh + e⁻(electron) + ve(electron antineutrino).

Beta decay is radioactive decay in which a beta ray and a neutrino are emitted from an atomic nucleus.There are two types of beta decay: beta minus and beta plus.

In beta minus decay, neutron is converted to a proton and an electron and an electron antineutrino.
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Given the reaction that occurs in an electrochemical cell: zn(s) + cuso4(aq) znso4(aq) + cu(s) during this reaction, the oxidation number of zn changes from
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Answer : The correct answer is oxidation number of Zn changes from 0 to +2.

Oxidation number :

It is number given to an element when it undergoes oxidation by loosing electrons . Oxidation number is equal to number of electrons donated . It is generally represented as charge .

Oxidation number of any element in a compound can be calculated as :

(Total number of positive charge) + (total number of negative charge) = total charge on compound

Where : Total positive charge = No. of atom or polyatomic molecule * positive charge on it

Total negative charge = No. of atom or polyatomic molecule * negative charge on it

Total charge on compound = Charge lying on top of compound .

Following steps can be used to find change in oxidation number of Zn :

Step 1 ) : To find oxidation number of Zn ( reactant side ) :

On reactant side Zn is present in solid state or its elemental state . It is not attached to any other atom , hence it is neutral and isolated atom. So oxidation number on Zn(s) is 0 .

Step 2: To find oxidation number of Zn in ZnSO₄ (aq)

ZnSO₄(aq) is ionic compound compound . It has two ions in it, Zn and SO₄ . Also it is a neutral compound means it has zero charge on it .

SO₄ is sulfate which has -2 charge or oxidation number on it (image attached )and there is one molecule of SO₄ ion . There is one atom of Zn which has unknown charge or oxidation number (x) .

To calculate oxidation number on Zn ion , plug values in above formula :

(No of Zn atom * charge on it ) + (No of SO₄ molecule * charge on it ) = Total charge on ZnSO₄

( 1* charge on Zn ) + ( 1* -2 ) = 0

Charge on Zn + (-2) = 0

Charge on Zn = +2

On reactant side Zn(s) has Zero charge and on product side Zn in ZnSO₄(aq) has +2 charge .

Hence the charge in oxidation number of Zn is from 0 to +2 .

Solution 2
0 to +2 is the answer to this question
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For a reaction to be spontaneous under standard conditions at all temperatures, the signs of ΔH° and ΔS° must be negative and positive, respectively.
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